Lesson 14 of 1910 minutes

Rotational Energy and Angular Momentum

Start with the lesson question, connect the representations, and test the model with evidence.

rotational kinetic energyangular momentumangular impulserolling without slippingconservation

Learning objectives

  • Model rotational kinetic energy.
  • Relate angular impulse and angular momentum.
  • Analyze coupled translation and rotation.
Lesson flowHook, model, explanationShow guidance

Inspect the opening phenomenon

Predict what changes, then name the evidence.

Apply in the lab

Name the evidence before reading the answer.

Read only what helps

Then use the lab and recall check.

More when needed

Transcript and resources stay available below.

Course progress

AP Physics 1 — Algebra-Based · Energy and Momentum of Rotating Systems · Lesson 14

Rotational Energy and Angular Momentum

In progress

Decision challenge

Observe the phenomenon. Then connect the representations.

Use the opening example to make a prediction, identify evidence, and explain which model supports it.

Pull In, Spin Faster | AP Physics 1

Predict what happens to angular speed when a rotating student pulls two masses inward with negligible external torque.

Predict the final angular speed and decide whether rotational kinetic energy is also conserved.

Before

Predict what happens to angular speed when a rotating student pulls two masses inward with negligible external torque.

During

Pause at 4.0 times 2.0 equals 1.6 times final angular speed. Solve for the final value before it appears.

After

Explain why angular momentum remains constant while rotational kinetic energy increases during the inward pull.

Reference drawerTranscript, source notes, scripts, and package status stay tucked away until you need them.7 files

Lesson reading

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10 min

Video script

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courses/ap-physics-1/modules/06-energy-and-momentum-of-rotating-systems/lessons/01-rotational-energy-and-angular-momentum/video-transcript.md

Rolling Energy and Rotational Inertia

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1 hr 30 min

Mastery check

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7 questions / 15 min

Book section:courses/ap-physics-1/modules/06-energy-and-momentum-of-rotating-systems/lessons/01-rotational-energy-and-angular-momentum/book-section.md
Transcript for accessibility and fallback

# Accessible transcript: Pull In, Spin Faster How can you spin faster without a motor? On a low-friction stool, pull two masses inward. Your rotational inertia drops. With almost no external torque, angular momentum stays constant: four times two equals one point six times final angular speed. Final angular speed is five radians per second. Quick check: if angular momentum stayed constant, did rotational kinetic energy also stay constant? Pause. No. It increased because pulling inward required internal work. Momentum and energy need separate audits. Learn free at EduQuest AI. ## Visual description A rotating figure begins with masses extended and then pulls them inward. Momentum bars remain equal while angular speed rises from two to five radians per second and an energy meter rises, emphasizing separate conservation tests.

Reading lab

Core explanation

Connect the lesson's words, diagrams, graphs, evidence, and equations.

Driving question

Which quantities remain useful or conserved in rotating systems?

Before learning: spinning-student prediction

A student rotates on a low-friction stool while holding two masses. Predict what happens to angular speed when the masses move inward. Then decide whether angular momentum, rotational kinetic energy, both, or neither must remain constant.

Hook: pull inward, spin faster—with no motor

Moving mass inward reduces rotational inertia. If external torque is negligible, angular momentum stays constant, so angular speed increases. But rotational kinetic energy can increase because the student does internal work while pulling.

A rotating person changes from extended to compact mass distribution

Rotational kinetic energy

For a rigid body rotating about a fixed axis,

Krot=12Iω2.K_{rot}=\frac12I\omega^2.

Rotational inertia II depends on mass distribution and axis. Angular speed ω\omega is shared by every point of a rigid body, but linear speed depends on radius:

v=rω.v=r\omega.

Points farther from the axis move faster linearly.

Worked example: flywheel energy

A flywheel with I=0.80 kgm2I=0.80\text{ kg}\cdot\text{m}^2 rotates at 6.0 rad/s6.0\text{ rad/s}:

Krot=12(0.80)(6.0)2=14.4 J.K_{rot}=\frac12(0.80)(6.0)^2=14.4\text{ J}.

Doubling angular speed would quadruple its rotational kinetic energy.

Work and power in rotation

For constant torque through angular displacement,

W=τΔθ.W=\tau\Delta\theta.

Instantaneous rotational power is

P=τω.P=\tau\omega.

Torque and energy both use Nm\text{N}\cdot\text{m} dimensionally, but torque is a signed rotational effect while energy is a scalar measured in joules.

Angular momentum and angular impulse

For a rigid body rotating about a fixed symmetry axis,

L=Iω.\vec L=I\vec\omega.

The general relationship between external torque and angular momentum is

τexternal=dLdt.\sum\vec\tau_{external}=\frac{d\vec L}{dt}.

Angular impulse changes angular momentum:

τexternaldt=ΔL.\int\sum\vec\tau_{external}\,dt=\Delta\vec L.

Signed area under a net-external-torque-versus-time graph equals angular-momentum change.

Torque-time graph with shaded angular impulse area

Conservation of angular momentum

If net external torque is zero or its angular impulse is negligible over the interval,

LiLf.\vec L_i\approx\vec L_f.

For a rotating body whose distribution changes,

Iiωi=Ifωf.I_i\omega_i=I_f\omega_f.

Worked example: pulling masses inward

A rotating system changes from Ii=4.0 kgm2I_i=4.0\text{ kg}\cdot\text{m}^2 at ωi=2.0 rad/s\omega_i=2.0\text{ rad/s} to If=1.6 kgm2I_f=1.6\text{ kg}\cdot\text{m}^2. With negligible external angular impulse,

ωf=IiωiIf=5.0 rad/s.\omega_f=\frac{I_i\omega_i}{I_f}=5.0\text{ rad/s}.

Initial energy is 8.0 J8.0\text{ J} and final energy is 20 J20\text{ J}. Angular momentum is conserved; kinetic energy increases because internal biochemical energy is transferred by work.

Rolling without slipping

A rolling object's kinetic energy includes translation and rotation:

K=12Mvcm2+12Icmω2.K=\frac12Mv_{cm}^2+\frac12I_{cm}\omega^2.

For rolling without slipping,

vcm=Rω.v_{cm}=R\omega.

Rolling disk with translation and rotation labels

A rolling object does not have only translational energy. Objects with different I/(MR2)I/(MR^2) ratios partition energy differently and can have different accelerations down the same incline.

Worked example: rolling solid cylinder

For a solid cylinder, Icm=12MR2I_{cm}=\frac12MR^2. At speed vv without slipping,

K=12Mv2+12(12MR2)(vR)2=34Mv2.K=\frac12Mv^2+\frac12\left(\frac12MR^2\right)\left(\frac{v}{R}\right)^2 =\frac34Mv^2.

One-third of the total kinetic energy is rotational and two-thirds translational.

During learning: conservation audit

  1. Name the system, axis, and interval.
  2. Identify external torques and estimate whether their angular impulse is negligible.
  3. Distinguish angular-momentum conservation from mechanical-energy conservation.
  4. For rolling, include both energy terms and justify the no-slip constraint.
  5. Check whether all points share ω\omega, not vv.

Misconception clinic

“Angular momentum is conserved in every rotation.” It changes when net external angular impulse is nonzero.

“If angular momentum is conserved, kinetic energy is conserved.” Internal work can change kinetic energy while LL remains constant.

“A rolling object has only translational energy.” It also rotates about its center of mass.

“All points on a rigid body have the same linear speed.” They share angular speed; v=rωv=r\omega varies with radius.

“Static friction always removes mechanical energy.” In ideal rolling without slipping on a fixed surface, static friction may do no work at the contact point.

After learning: retrieval and transfer

  1. How does doubling ω\omega affect KrotK_{rot} at fixed II?
  2. What does area under a net-torque-time graph represent?
  3. Why can pulling masses inward increase rotational kinetic energy while conserving angular momentum?
  4. Write the complete kinetic energy for rolling without slipping.
  5. What external interaction would make angular momentum about a chosen axis fail to be conserved?

AP-style evidence routine

  1. Choose system, axis, and interval.
  2. Inventory energy transfers and external torques.
  3. Decide which conservation statements are justified independently.
  4. Write relationships symbolically before substitution.
  5. Apply vcm=Rωv_{cm}=R\omega only for verified no-slip rolling.
  6. Check units, signs, energy accounting, and limiting cases.

Key takeaway

Angular momentum is controlled by external angular impulse, while rotational energy is controlled by work and energy transfer. Conservation of one never automatically guarantees conservation of the other.

Further learning and alignment

Practice labRolling Energy and Rotational InertiaOpen this when you are ready to apply the model, collect evidence, and check your explanation.1 hr 30 min

Lab: Rolling Energy and Rotational Inertia

Objective

How does mass distribution affect the acceleration and energy partition of objects rolling without slipping down an incline?

Safety

Work under teacher or responsible-adult supervision. Secure a low-angle ramp, use low-mass blunt rolling objects, install a soft catch box, keep the lane and floor clear, and release without pushing. Do not use glass, sharp, motorized, or high-speed objects. Stop if slipping or ramp movement occurs.

Materials

  • secure adjustable ramp with measured height and length;
  • equal-radius or measured-radius rolling objects with different mass distributions, such as a solid cylinder and hoop;
  • balance and caliper/ruler;
  • photogates, motion sensor, or fixed slow-motion video with scale;
  • soft stop and high-contrast markers.

Low-cost alternative: sealed cans whose contents do not shift, verified to roll safely, plus phone video.

Simulation alternative: teacher-approved rolling simulation. Export raw data and identify idealizations.

Steps

  1. Measure mass, radius, ramp height, and ramp distance with instrument resolution.
  2. Identify each object's theoretical or experimentally justified I/(MR2)I/(MR^2) factor.
  3. Predict the order of arrival and final speeds using energy models.
  4. Mark a common start line and release each object without pushing.
  5. Record at least five trials per object over the same distance.
  6. Determine acceleration or final speed from fitted video/sensor data.
  7. Check rolling without slipping using visible rotation markers and vRωv\approx R\omega.
  8. Preserve all raw data and document excluded trials.

Expected Result

Objects with smaller I/(MR2)I/(MR^2) should accelerate more and reach the bottom sooner under the ideal no-slip model because a smaller fraction of gravitational energy enters rotation.

Analysis

Use

Mgh=12Mv2+12Iv2R2Mgh=\frac12Mv^2+\frac12I\frac{v^2}{R^2}

to predict bottom speed. Compare prediction and measurement with uncertainty.

  • Report trial means, spread, and instrument uncertainty.
  • Compare translational and rotational kinetic-energy fractions.
  • Test whether mass cancels from the ideal prediction.
  • Discuss rolling resistance, deformation, air drag, ramp uncertainty, radius measurement, internal shifting, and slipping.

Reflection Questions

  1. Why is translational energy alone insufficient?
  2. Which object devoted the largest energy fraction to rotation?
  3. Did greater total mass guarantee earlier arrival? Explain.
  4. What evidence supports or challenges the no-slip assumption?

Claim-evidence-reasoning conclusion

Claim how mass distribution affected motion. Cite measured speeds/times and uncertainties, then connect evidence to rotational inertia and energy partition.

Accessibility

Provide safety, release, timing, tactile inspection, recording, analysis, and narration roles. Use high-contrast markers, tactile ramp edges, large-print/screen-reader tables, and verbal graph descriptions. Analysis can use shared data without physical handling.

Extension Challenge

Use measured motion to estimate an object's dimensionless inertia factor I/(MR2)I/(MR^2), compare it with the expected shape model, and evaluate agreement within uncertainty.