Lesson 11 of 195 minutes

Center of Mass and Collision Models

Start with the lesson question, connect the representations, and test the model with evidence.

center of masssystem momentumelastic collisioninelastic collisionreference frames

Learning objectives

  • Relate impulse and momentum change.
  • Apply momentum conservation to collisions and explosions.
  • Evaluate when a momentum model is valid.
Lesson flowHook, model, explanationShow guidance

Inspect the opening phenomenon

Predict what changes, then name the evidence.

Apply in the lab

Name the evidence before reading the answer.

Read only what helps

Then use the lab and recall check.

More when needed

Transcript and resources stay available below.

Course progress

AP Physics 1 — Algebra-Based · Linear Momentum · Lesson 11

Center of Mass and Collision Models

In progress

Decision challenge

Observe the phenomenon. Then connect the representations.

Use the opening example to make a prediction, identify evidence, and explain which model supports it.

An Explosion That Doesn't Move the System | AP Physics 1

Predict whether the center of mass moves when a stationary cart separates into two pieces with negligible external impulse.

Track total momentum and center-of-mass motion, then compare the speeds of unequal-mass pieces.

Before

Predict whether the center of mass moves when a stationary cart separates into two pieces with negligible external impulse.

During

Pause when the center-of-mass velocity equation appears and connect it to total momentum.

After

Explain why the lighter piece moves faster when the pieces have equal-magnitude opposite momenta.

Reference drawerTranscript, source notes, scripts, and package status stay tucked away until you need them.7 files

Lesson reading

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5 min

Video script

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Transcript fallback

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courses/ap-physics-1/modules/04-linear-momentum/lessons/02-center-of-mass-and-collision-models/video-transcript.md

Track Center of Mass Through Collisions

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1 hr 25 min

Mastery check

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7 questions / 15 min

Book section:courses/ap-physics-1/modules/04-linear-momentum/lessons/02-center-of-mass-and-collision-models/book-section.md
Transcript for accessibility and fallback

# Accessible transcript: An Explosion That Doesn't Move the System An explosion can send pieces flying while the system stays put. Track the center of mass: the mass-weighted average position of all pieces. Center-of-mass velocity equals total momentum divided by total mass. If the cart starts at rest and external impulse is negligible, total momentum stays zero. The pieces get equal and opposite momenta, so the center of mass remains at rest. Quick check: which piece moves faster, the lighter or heavier one? Pause. The lighter piece, because equal momentum means speed is inversely proportional to mass. Learn momentum free at EduQuest AI. ## Visual description A stationary cart separates into unequal pieces moving opposite directions. Equal-length momentum arrows point away while a center-of-mass marker stays fixed. The lighter piece's velocity arrow is longer.

Reading lab

Core explanation

Connect the lesson's words, diagrams, graphs, evidence, and equations.

Driving question

How can a complicated many-object interaction be described by one system point and a small set of conservation tests?

Before learning: exploding cart prediction

Two unequal pieces push apart from a cart initially at rest on a nearly frictionless track. Sketch each piece's motion and predict the center-of-mass motion. Which piece moves faster?

Hook: an explosion can leave the center of mass unmoved

Internal forces can send pieces in opposite directions while the system center of mass remains at rest. Only net external force changes center-of-mass momentum.

Center-of-mass position

For particles,

rcm=imiriimi.\vec r_{cm}=\frac{\sum_i m_i\vec r_i}{\sum_i m_i}.

In one dimension,

xcm=m1x1+m2x2+M.x_{cm}=\frac{m_1x_1+m_2x_2+\cdots}{M}.

The center lies closer to the larger mass and can lie in empty space.

Two unequal masses with center of mass closer to the larger mass

Worked example

A 2.0 kg2.0\text{ kg} mass is at x=0x=0 and a 6.0 kg6.0\text{ kg} mass at x=4.0 mx=4.0\text{ m}:

xcm=(2)(0)+(6)(4)8=3.0 m.x_{cm}=\frac{(2)(0)+(6)(4)}{8}=3.0\text{ m}.

Center-of-mass velocity and momentum

vcm=imiviM=psystemM.\vec v_{cm}=\frac{\sum_i m_i\vec v_i}{M}=\frac{\vec p_{system}}{M}.

Therefore

psystem=Mvcm\vec p_{system}=M\vec v_{cm}

and

Fexternal=Macm.\sum\vec F_{external}=M\vec a_{cm}.

Internal interaction forces change individual velocities but not vcm\vec v_{cm} when external impulse is negligible.

Colliding carts change individual velocity while center of mass moves uniformly

Collision model selection

All collision analyses begin with system and external impulse. If external impulse is negligible,

pi=pf.\vec p_i=\vec p_f.

Additional conditions depend on evidence:

  • perfectly inelastic: objects stick and share final velocity;
  • elastic: total kinetic energy is also conserved;
  • general inelastic: momentum conserved, kinetic energy changes, and another measured condition may be needed.

Decision tree for selecting a collision model

Kinetic-energy test

Define

Ki=12mivi2,Kf=12mivf2.K_i=\sum\frac12m_iv_{i}^2,\qquad K_f=\sum\frac12m_iv_f^2.

Momentum is a vector; kinetic energy is a scalar. A collision can conserve momentum while kinetic energy transfers to thermal energy, sound, deformation, or rotation.

Worked sticking collision

A 1.0 kg1.0\text{ kg} cart at +4.0 m/s+4.0\text{ m/s} sticks to a 3.0 kg3.0\text{ kg} cart at rest:

vf=(1)(4)+(3)(0)4=1.0 m/s.v_f=\frac{(1)(4)+(3)(0)}{4}=1.0\text{ m/s}.

Ki=8.0 JK_i=8.0\text{ J} and Kf=2.0 JK_f=2.0\text{ J}. Momentum is conserved; 6.0 J6.0\text{ J} leaves macroscopic translational kinetic energy.

Elastic collision in the center-of-mass frame

The center-of-mass frame moves at vcmv_{cm}. In a one-dimensional elastic collision, velocities relative to the center of mass reverse while retaining magnitudes. Transforming back gives lab-frame final velocities. This is a model insight, not a replacement for checking energy and momentum.

Explosions and separation

An explosion begins with stored internal energy. If initial system momentum is zero and external impulse negligible,

m1v1+m2v2=0.m_1\vec v_1+m_2\vec v_2=0.

Pieces have equal and opposite momenta; the lighter piece has greater speed. Kinetic energy may increase as stored energy is released.

During learning: collision audit

  1. Define system, interval, axes, and observer frame.
  2. Evaluate external impulse.
  3. Calculate vcm\vec v_{cm} before and after.
  4. Apply momentum conservation only when justified.
  5. Test kinetic energy separately and add only evidence-supported constraints.

Misconception clinic

“Center of mass must be inside an object.” It can lie in empty space.

“The center of mass follows the largest object.” Its acceleration follows net external force.

“Every collision conserves kinetic energy.” Only elastic collisions do.

“Momentum is conserved for each object.” Interaction impulse changes individual momentum.

“An explosion violates momentum conservation.” Stored energy changes kinetic energy while total momentum remains controlled by external impulse.

After learning: retrieval and transfer

  1. Why is center of mass closer to the larger mass?
  2. What determines center-of-mass acceleration?
  3. What extra condition defines a perfectly inelastic collision?
  4. How can kinetic energy increase in an explosion?
  5. What is special about elastic velocities in the center-of-mass frame?

AP-style evidence routine

  1. Choose system, frame, interval, and axes.
  2. Compute system momentum and center-of-mass velocity.
  3. Audit external impulse.
  4. Select collision constraints from evidence.
  5. Solve and test momentum, kinetic energy, direction, units, and limiting cases.

Key takeaway

The center of mass converts many-object motion into a system-level model. External force controls that point; collision details determine how momentum and energy are distributed internally.

Further learning and alignment

Practice labTrack Center of Mass Through CollisionsOpen this when you are ready to apply the model, collect evidence, and check your explanation.1 hr 25 min

Lab: Track Center of Mass Through Collisions

Objective

Does the center of mass move at approximately constant velocity during different two-cart collisions when external impulse is small?

Safety

Teacher supervision is required. Secure a low-friction track with soft stops, use low-speed carts, keep hands/feet clear, inspect bumpers and couplers, and place cameras outside the path. Do not use projectiles, heavy carts, or modified springs.

Materials

  • two carts with measured masses;
  • level track, elastic-like bumpers, and sticking coupler;
  • overhead/side video or motion sensors;
  • scale markers and soft stops.

Low-cost alternative: two low-mass toy carts on a marked smooth floor.

Simulation alternative: approved collision simulation with exported position-time data.

Steps

  1. Measure masses and define axis/system.
  2. Record at least three elastic-like and three sticking collisions at low speed.
  3. Extract simultaneous x1(t)x_1(t) and x2(t)x_2(t) values before, during, and after.
  4. Calculate xcm(t)=(m1x1+m2x2)/(m1+m2)x_{cm}(t)=(m_1x_1+m_2x_2)/(m_1+m_2).
  5. Fit center-of-mass velocity before and after each collision.
  6. Calculate system momentum and kinetic energy before/after.
  7. Preserve raw data and anomalies.

Expected Result

Center-of-mass velocity and system momentum should remain approximately constant within uncertainty, while kinetic energy changes more in sticking collisions.

Analysis

  • Compare fitted vcmv_{cm} before/after with uncertainty.
  • Compare momentum discrepancy and kinetic-energy change.
  • Discuss track tilt, friction, timing alignment, perspective, rotating wheels, and collision interval.
  • Inspect residuals of xcm(t)x_{cm}(t) linear fits.

Reflection Questions

  1. Why can individual cart velocities jump while vcmv_{cm} remains smooth?
  2. Which collisions lost more translational kinetic energy?
  3. How would track tilt appear in xcm(t)x_{cm}(t) residuals?
  4. Could xcmx_{cm} lie between carts in empty space?

Claim-evidence-reasoning conclusion

Claim whether center-of-mass motion supported negligible external impulse. Cite slopes, momentum, energy, and uncertainty.

Accessibility

Offer safety, camera, tracking, data, graphing, uncertainty, and narration roles. Use high-contrast markers and screen-reader tables. Analysis may use shared/simulated data.

Extension Challenge

Transform measured velocities into the center-of-mass frame and test whether elastic-like collision velocities approximately reverse.