Lesson 18 of 1915 minutes

Pressure, Buoyancy, and Flow

Start with the lesson question, connect the representations, and test the model with evidence.

pressurehydrostaticsbuoyancyarchimedes principlecontinuitybernoulli

Learning objectives

  • Relate pressure and depth.
  • Analyze buoyancy with system diagrams.
  • Apply continuity and energy reasoning to ideal flow.
Lesson flowHook, model, explanationShow guidance

Inspect the opening phenomenon

Predict what changes, then name the evidence.

Apply in the lab

Name the evidence before reading the answer.

Read only what helps

Then use the lab and recall check.

More when needed

Transcript and resources stay available below.

Course progress

AP Physics 1 — Algebra-Based · Fluids · Lesson 18

Pressure, Buoyancy, and Flow

In progress

Decision challenge

Observe the phenomenon. Then connect the representations.

Use the opening example to make a prediction, identify evidence, and explain which model supports it.

Why Fluid Speeds Up in a Narrow Pipe | AP Physics 1

Predict how fluid speed changes when a steady incompressible stream enters a pipe section with half the cross-sectional area.

Predict the narrow-section speed and identify the assumptions needed to compare static pressure.

Before

Predict how fluid speed changes when a steady incompressible stream enters a pipe section with half the cross-sectional area.

During

Pause at the area and speed values. Use area one times speed one equals area two times speed two before the result appears.

After

Explain why greater speed implies lower static pressure only when Bernoulli's steady ideal-flow assumptions and height are accounted for.

Reference drawerTranscript, source notes, scripts, and package status stay tucked away until you need them.7 files

Lesson reading

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15 min

Video script

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Transcript fallback

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courses/ap-physics-1/modules/08-fluids/lessons/01-pressure-buoyancy-and-flow/video-transcript.md

Test Archimedes' Principle by Displacement

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1 hr 25 min

Mastery check

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7 questions / 15 min

Book section:courses/ap-physics-1/modules/08-fluids/lessons/01-pressure-buoyancy-and-flow/book-section.md
Transcript for accessibility and fallback

# Accessible transcript: Why Fluid Speeds Up in a Narrow Pipe Why does water speed up when a pipe narrows? For steady incompressible flow, the same volume must cross every section each second. Area one is four square centimeters at two meters per second. Area two is half as large, so continuity makes speed twice as large: four meters per second. At equal height in ideal flow, Bernoulli says that greater speed comes with lower static pressure. Quick check: does faster fluid always mean lower pressure? Pause. No. That conclusion needs steady, ideal flow and height accounting. Learn fluids free at EduQuest AI. ## Visual description A horizontal streamtube narrows from four to two square centimeters. Equally spaced flow-volume markers move twice as fast in the narrow section. Pressure gauges show lower ideal static pressure there, followed by an assumptions warning.

Reading lab

Core explanation

Connect the lesson's words, diagrams, graphs, evidence, and equations.

Driving question

How do pressure, density, flow, and energy models explain fluid behavior?

Before learning: three predictions

Predict which statement is correct: (1) water pressure depends on container shape, (2) a floating object's buoyant force exceeds its weight, or (3) fluid speeds up in a narrower pipe. Explain each prediction before calculating.

Hook: a narrow pipe makes fluid speed up

For steady incompressible flow, the same volume must pass each cross-section per time. A smaller area means greater speed—not because fluid “wants” to accelerate, but because mass is conserved.

Density and pressure

Density is

ρ=mV.\rho=\frac{m}{V}.

Pressure is normal force per area:

P=FA.P=\frac{F_\perp}{A}.

Pressure is a scalar measured in pascals, 1 Pa=1 N/m21\text{ Pa}=1\text{ N/m}^2. Pressure is not force; force on a flat surface requires pressure and area.

Hydrostatic pressure

In a fluid at rest of approximately constant density,

P=P0+ρgh.P=P_0+\rho gh.

hh is vertical depth below the reference surface. At the same depth in the same connected fluid, pressure is the same regardless of container shape.

Three differently shaped vessels with equal pressure at equal depth

Worked example: pool pressure

At 3.0 m3.0\text{ m} below a freshwater surface, gauge pressure is

Pg=(1000)(9.8)(3.0)=2.94×104 Pa.P_g=(1000)(9.8)(3.0)=2.94\times10^4\text{ Pa}.

Absolute pressure adds atmospheric pressure; gauge pressure does not.

Pascal's principle and hydraulic systems

An externally applied pressure change in an enclosed fluid is transmitted throughout the fluid. For ideal pistons at the same height,

F1A1=F2A2.\frac{F_1}{A_1}=\frac{F_2}{A_2}.

Force can be multiplied, but energy cannot: the larger piston moves a smaller distance so ideal input and output work agree.

Buoyant force

Pressure increases with depth, so a submerged object typically experiences a larger upward pressure force on its bottom than the downward force on its top. The resulting buoyant force equals the weight of displaced fluid:

FB=ρfluidgVdisplaced.F_B=\rho_{fluid}gV_{displaced}.

Pressure forces on a submerged block combine into buoyant force

For a floating object in equilibrium,

FB=mg.F_B=mg.

The displaced volume adjusts until this is true. Buoyant force does not always equal object weight: a held submerged object or accelerating object can have other forces.

Worked example: floating fraction

A block of density 750 kg/m3750\text{ kg/m}^3 floats in water of density 1000 kg/m31000\text{ kg/m}^3. Force balance gives

ρwatergVsub=ρblockgV,\rho_{water}gV_{sub}=\rho_{block}gV,

so

VsubV=0.750.\frac{V_{sub}}{V}=0.750.

Seventy-five percent of its volume is submerged.

Continuity: mass conservation in flow

For steady incompressible flow,

A1v1=A2v2.A_1v_1=A_2v_2.

Streamtube narrowing with velocity increasing

If pipe area halves, speed doubles. This relationship alone does not determine pressure.

Bernoulli's equation: energy along a streamline

For steady, incompressible, nonviscous flow along a streamline with no pump/turbine energy added or removed,

P+12ρv2+ρgy=constant.P+\frac12\rho v^2+\rho gy=\text{constant}.

At equal height in this ideal model, greater speed corresponds to lower static pressure. “Faster fluid always has lower pressure” is too broad: height, viscosity, pumps, unsteady flow, and streamline choice matter.

Worked example: level constriction

Water flows from area 4.0 cm24.0\text{ cm}^2 at 2.0 m/s2.0\text{ m/s} into area 2.0 cm22.0\text{ cm}^2. Continuity gives v2=4.0 m/sv_2=4.0\text{ m/s}. At equal height,

P1P2=12ρ(v22v12)=6.0×103 Pa.P_1-P_2=\frac12\rho(v_2^2-v_1^2)=6.0\times10^3\text{ Pa}.

During learning: model audit

  1. Distinguish absolute pressure, gauge pressure, pressure force, and buoyant force.
  2. Define the system and draw all external forces.
  3. For flow, test steady, incompressible, nonviscous, and streamline assumptions.
  4. Use continuity for volume-flow constraints and Bernoulli for energy—not interchangeably.
  5. Check area units carefully: 1 cm2=104 m21\text{ cm}^2=10^{-4}\text{ m}^2.

Misconception clinic

“Pressure is a force.” Pressure is force per area.

“Deeper pressure depends on container shape.” Hydrostatic pressure depends on depth, density, gravity, and surface pressure.

“Buoyant force always equals object weight.” That equality applies to vertical equilibrium with buoyancy and weight as the only vertical forces.

“A larger object always floats.” Average density and displaced-fluid capacity matter, not size alone.

“Faster fluid always has greater pressure.” Under restricted ideal equal-height conditions, faster flow corresponds to lower static pressure.

After learning: retrieval and transfer

  1. Why is pressure equal at equal depth in a connected static fluid?
  2. What determines the submerged fraction of a floating uniform object?
  3. If pipe diameter halves, by what factor does area change and speed change?
  4. State the assumptions behind Bernoulli's equation.
  5. Explain why hydraulic force multiplication does not multiply energy.

AP-style evidence routine

  1. Choose system, reference pressure, and vertical coordinate.
  2. Draw pressure forces or a free-body diagram.
  3. Select hydrostatic, buoyancy, continuity, or energy model based on evidence.
  4. State assumptions and write relationships symbolically.
  5. Convert areas/volumes, solve, and check units, signs, limits, and physical plausibility.

Key takeaway

Fluid behavior follows force, mass, and energy accounting. Pressure fields explain buoyancy; continuity constrains flow speed; Bernoulli connects pressure, speed, and height only under stated ideal conditions.

Further learning and alignment

Practice labTest Archimedes' Principle by DisplacementOpen this when you are ready to apply the model, collect evidence, and check your explanation.1 hr 25 min

Lab: Test Archimedes' Principle by Displacement

Objective

Does the loss of apparent weight of a submerged object equal the weight of displaced water within uncertainty?

Safety

Work under teacher supervision. Use only water and nonreactive, nonsharp, low-mass objects. Keep water away from outlets/electronics, wipe spills immediately, use a stable container below eye level, never taste lab water, and wash hands afterward. Do not submerge powered devices.

Materials

  • spring scale or force sensor on a secure stand;
  • overflow can or graduated container;
  • collection cup and balance;
  • water, tray, towels;
  • several nonporous objects and thin string.

Low-cost alternative: calibrated elastic force scale, kitchen measuring cup, and digital kitchen balance in a spill tray.

Simulation alternative: approved buoyancy simulation with raw readings; identify omitted surface tension, sensor, and spill losses.

Steps

  1. Measure object weight in air and sensor resolution.
  2. Fill/prepare the overflow container and tare the collection cup.
  3. Predict the scale reading when fully submerged without touching bottom/sides.
  4. Submerge slowly, remove bubbles, and record apparent weight.
  5. Collect displaced water and measure its mass or volume.
  6. Repeat at least three times per object and use at least three objects.
  7. Preserve raw readings, spill notes, bubbles, and excluded trials.
  8. Compare WairWsubmergedW_{air}-W_{submerged} with mwatergm_{water}g.

Expected Result

The apparent-weight loss should agree with displaced-water weight within experimental uncertainty.

Analysis

  • Calculate buoyant force by both methods.
  • Graph apparent-weight loss versus displaced-water weight with a slope-one reference.
  • Include sensor, balance, volume, and repeatability uncertainty.
  • Discuss trapped bubbles, surface tension, string buoyancy, incomplete submersion, spill loss, object contact, and water retained on surfaces.

Reflection Questions

  1. Why must the object not touch the container?
  2. How would trapped air affect results?
  3. Does greater depth change buoyant force for a rigid fully submerged object in constant-density water?
  4. Which measurement dominated uncertainty?

Claim-evidence-reasoning conclusion

Claim whether evidence supports Archimedes' principle. Cite paired buoyant-force estimates and uncertainties, then link pressure difference to displaced-fluid weight.

Accessibility

Offer spill safety, tactile object inspection, scale reading, collection, recording, analysis, and oral-report roles. Use large-print/high-contrast scales and screen-reader tables. Analysis may use shared data without water handling.

Extension Challenge

Predict the submerged fraction of a safe floating object from its measured mass and external volume, then measure the fraction and compare within uncertainty.